Q. The time period of oscillation of a bar magnet suspended horizontally along the magnetic meridian is $T_{0}$. If this magnet is replaced by another magnet of the same size and pole strength but with double the mass, the new time period will be
A) $\frac{T_{0}}{2}$
B) $\frac{T_{0}}{\sqrt{2}}$
C) $\sqrt{2}T_{0}$
D) $2T_{0}$
Explanation
(c) $T = 2\pi\sqrt{\frac{1}{MB_{H}}} \Rightarrow T \propto \sqrt{I} \propto \sqrt{w} \Rightarrow T^{'} = \sqrt{2}\ T_{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.