Magnets $A$ and $B$ are geometrically similar but the magnetic moment of $A$ is twice that of $B$. If $T_{1}$ and $T_{2}$ be the time periods of the oscillation when their like poles and unlike poles are kept together respectively, then $\frac{T_{1}}{T_{2}}$ will be

Question

Dr. Abubacker · Accepted Answer

(c) $T_{Sum} = 2\pi\sqrt{\frac{(I_{1} + I_{2})}{\left( M_{1} + M_{2} \right)B_{H}}}$
$T_{diff} = 2\pi\sqrt{\frac{I_{1} + I_{2}}{\left( M_{1} - M_{2} \right)B_{H}}}$
$\Rightarrow \frac{T_{s}}{T_{d}} = \frac{T_{1}}{T_{2}} = \sqrt{\frac{M_{1} - M_{2}}{M_{1} + M_{2}}} = \sqrt{\frac{2M - M}{2M + M}} = \frac{1}{\sqrt{3}}$

Q. Magnets $A$ and $B$ are geometrically similar but the magnetic moment of $A$ is twice that of $B$. If $T_{1}$ and $T_{2}$ be the time periods of the oscillation when their like poles and unlike poles are kept together respectively, then $\frac{T_{1}}{T_{2}}$ will be

Explanation

Reviewed by Dr. Abubacker

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