A bar magnet of length $3\ cm$ has points $A$ and $B$ along its axis at distances of $24\ cm$ and $48\ cm$ on the opposite sides. Ratio of magnetic fields at these points will be [image:5_image33.emf]

Question

Dr. Abubacker · Accepted Answer

(a) Both points $A$ and $B$ lie on axial position
$B \propto \frac{1}{d^{3}} \Rightarrow \frac{B_{A}}{B_{B}} = \left( \frac{d_{B}}{d_{A}} \right)^{3} = \left( \frac{48}{24} \right)^{3} = \frac{8}{1}$

Q. A bar magnet of length $3\ cm$ has points $A$ and $B$ along its axis at distances of $24\ cm$ and $48\ cm$ on the opposite sides. Ratio of magnetic fields at these points will be

Explanation

Reviewed by Dr. Abubacker

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