Q. A magnet when placed perpendicular to a uniform field of strength $10^{- 4}Wb/m^{2}$ experiences a maximum couple of moment $4 \times 10^{- 5}N/m$. What is its magnetic moment
A) $0.4A \times m^{2}$
B) $0.2A \times m^{2}$
C) $0.16A \times m^{2}$
D) $0.04A \times m^{2}$
Explanation
(a) $C_{\max} = MB \Rightarrow 4 \times 10^{- 5} = M \times 10^{- 4} \Rightarrow M = 0.4\ A \times m^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.