Two uniform magnetic fields $B$ and $H$ are perpendicular to each other at a place. When a magnetic needle is placed in the field, it rest making angle $60{^\circ}$ and $30{^\circ}$ with $B$ and $H$ respectively. The value of $B:H$ is

Question

Dr. Abubacker · Accepted Answer

(d) $B = B_{0}\cos{60{^\circ}}$
$H = B_{0}\cos{30{^\circ}}$
$\frac{B}{H} = \frac{\cos{60{^\circ}}}{\cos{30{^\circ}}} = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}}$

Q. Two uniform magnetic fields $B$ and $H$ are perpendicular to each other at a place. When a magnetic needle is placed in the field, it rest making angle $60{^\circ}$ and $30{^\circ}$ with $B$ and $H$ respectively. The value of $B:H$ is

Explanation

Reviewed by Dr. Abubacker

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