(b) In tangent galvanometer, $I \propto \tan\theta$
$\therefore\frac{I_{1}}{I_{2}} = \frac{\tan\theta_{1}}{\tan\theta_{2}} \Rightarrow \frac{I_{1}}{I_{1}/\sqrt{3}} = \frac{\tan{45{^\circ}}}{\tan\theta_{2}}$
$\Rightarrow \sqrt{3}\tan{\theta_{2} = 1} \Rightarrow \tan\theta_{2} = \frac{1}{\sqrt{3}} \Rightarrow \ \theta_{2} = 30{^\circ}$
So deflection will decrease by $45{^\circ}$-$30{^\circ} = 15{^\circ}$