Q. A coil of area $80\ square\ cm$ and 50 turns is rotating with $2000\ revolutions\ per\ minute$ about an axis perpendicular to a magnetic filed of $0.05\ tesla$. The maximum value of the e.m.f. developed in it is
A) $200\ \pi\ volt$
B) $\frac{10\pi}{3}volt$
C) $\frac{4\pi}{3}volt$
D) $\frac{2}{3}volt$
Explanation
(c) $e = NBA\omega;\ \omega = 2\pi f = 2\pi \times \frac{2000}{60}$
$\therefore e = 50 \times 0.05 \times 80 \times 10^{- 4} \times 2\pi \times \frac{2000}{60} = \frac{4\pi}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.