(b) $V = 200V;r = 10\Omega$ $R^{'} = 10 + 100\Omega = 110\Omega$ $I = \frac{V}{R^{'}} = \frac{220}{110} = 2A$ $P = I^{2}R = 4 \times 100 = 400W$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.