Q. An AC generator of $220\ V$ having internal resistance $r = 10\ \Omega$ and external resistance $R = 100\ \Omega$. What is the power developed in the external circuit

A) $484\ W$
B) $400\ W$
C) $441\ W$
D) $369\ W$
Explanation

(b) $V = 200V;r = 10\Omega$
$R^{'} = 10 + 100\Omega = 110\Omega$
$I = \frac{V}{R^{'}} = \frac{220}{110} = 2A$
$P = I^{2}R = 4 \times 100 = 400W$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.