Q. A $10\ metre$ wire kept in east-west direction is falling with velocity $5m/sec$ perpendicular to the field $0.3 \times 10^{- 4}Wb/m^{2}$. The induced e.m.f. across the terminal will be
A) $0.15\ V$
B) $1.5\ mV$
C) $1.5\ V$
D) $15.0\ V$
Explanation
(b) Induced e.m.f. $= Blv = 0.3 \times 10^{- 4} \times 10 \times 5$
$= 1.5 \times 10^{- 3}V = 1.5\ mV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.