Q. A small piece of metal wire is dragged across the gap between the poles of a magnet in 0.4 s. If change in magnetic flux in the wire is $8 \times 10^{- 4}$ Wb, then emf induced in the wire is
A) $8 \times 10^{- 3}\ V$
B) $6 \times 10^{- 3}\ V$
C) $4 \times 10^{- 3}\ V$
D) $2 \times 10^{- 3}\ V$
Explanation
(d) $|e| = \frac{d\phi}{dt}$
$\ \ \ \ \ \ = \ \frac{8 \times 10^{- 4}}{0.4} = 2 \times 10^{- 3}V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.