(b) $e_{0} = \omega NBA = (2\pi v)NB\left( \pi r^{2} \right) = 2 \times \pi^{2}v\ NBr^{2}$ $= 2 \times (3.14)^{2} \times \frac{1800}{60} \times 4000 \times 0.5 \times 10^{- 4} \times \left( 7 \times 10^{- 2} \right)^{2}$ $= 0.58\ V$
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Ph.D. in Physics with 19+ years of teaching experience.