Q. A coil of $N$ turns and mean cross-sectional area $A$ is rotating with uniform angular velocity $\omega$ about an axis at right angle to uniform magnetic field $B$. The induced e.m.f. $E$ in the coil will be

A) $NBA\sin{\omega t}$
B) $NB\ \omega\sin{\omega t}$
C) $NB/A\ \ \sin\ \omega t$
D) $NBA\ \omega\sin{\omega t}$
Explanation

The correct answer is Option D: $NBA\ \omega\sin{\omega t}$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.