Q. An alternating current of frequency $200\ rad/sec$ peak value $1A$ as shown in the figure, is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is $1.5H$, the voltage induced in the secondary will be
A) $300\ V$
B) $191\ V$
C) $220\ V$
D) $471\ V$
Explanation
(b) $e = - M\frac{di}{dt} = - 1.5\frac{(1 - 0)}{(T/4)} = - \frac{6}{T},\ T = \frac{2\pi}{\omega} = \frac{2\pi}{200} = \frac{\pi}{100}$
$\Rightarrow |e| = \frac{600}{\pi} = 190.9\ V \approx 191V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.