A transformer has 100 turns in the primary coil and carries $8\ A$ current. If input power is one kilowatt, the number of turns required in the secondary coil to have $500V$ output will be

Question

Dr. Abubacker · Accepted Answer

(c) $P_{s} = V_{s}i_{s} \Rightarrow 1000 = V_{s} 	imes 8 \Rightarrow V_{s} = \frac{1000}{8}$
$\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}} \Rightarrow \frac{(1000/8)}{500} = \frac{100}{N_{s}} \Rightarrow N_{s} = 400$

Q. A transformer has 100 turns in the primary coil and carries $8\ A$ current. If input power is one kilowatt, the number of turns required in the secondary coil to have $500V$ output will be

Explanation

Reviewed by Dr. Abubacker

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