Q.
A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.5 second. The magnetic flux between the pole pieces is known to be $8 \times 10^{- 4}Wb$. The $emf$ induced in the wire is
A) $16\ mV$
B) $1.6\ V$
C) $1.6\ mV$
D) $16\ V$
Explanation
(c) As per Faraday’s Law of electromagnetic induction
$EMF = \frac{change\ in\ flux}{time} = \frac{8 \times 10^{- 4}Wb}{0.5\ \sec}$
$= 16 \times 10^{- 4}volt = 1.6\ mV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.