Q. A 50 mH coil carries a current of 2 A, the energy stored in joule is
A) 1
B) 0.05
C) 10
D) 0.1
Explanation
(d) Energy stored,
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ U = \frac{1}{2}Li^{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{1}{2} \times 50 \times 10^{- 3} \times 2 \times 2 = 0.1\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.