Q. In a step-up transformer the voltage in the primary is $220\ V$ and the current is $5A$. The secondary voltage is found to be $22000V$. The current in the secondary (neglect losses) is
A) $5\ A$
B) $50\ A$
C) $500\ A$
D) $0.05\ A$
Explanation
(d) $\frac{V_{p}}{V_{s}} = \frac{i_{s}}{i_{p}} \Rightarrow \frac{220}{22000} = \frac{i_{s}}{5} \Rightarrow i_{s} = 0.05\ amp$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.