Q. A conducting loop having a capacitor is moving outward from the magnetic field then which plate of the capacitor will be positive
A) Plate $- A$
B) Plate $- B$
C) Plate $- A$ and Plate $- B$ both
D) None
Explanation
(a) Crosses (×) linked with the loop are decreasing, so induced current in it is clockwise, $i.e$., from $B \rightarrow A$. Hence electrons flow from plate $A$ and $B$ so plate $A$ becomes positively charged
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.