As shown in the figure, $P$ and $Q$ are two coaxial conducting loops separated by some distance. When the switch $S$ is closed, a clockwise current $I_{P}$ flows in $P$ (as seen by $E$) and an induced current $I_{Q_{1}}$ flows in $Q$. The switch remains closed for a long time. When $S$ is opened, a current $I_{Q_{2}}$ flows in $Q$. Then the directions of $I_{Q_{1}}$ and $I_{Q_{2}}$ (as seen by $E$) are

Question

Dr. Abubacker · Accepted Answer

(d) When switch $S$ is closed magnetic field lines passing through $Q$ increases in the direction from right to left. So, according to Lenz’s law induced current in $Q\ i.e.$ $I_{Q_{1}}$ will flow in such a direction so that the magnetic field lines due to $I_{Q_{1}}$ passes from left to right through $Q$. This is possible when $I_{Q_{1}}$ flows in anticlockwise direction as seen by $E$. Opposite is the case when switch $S$ is opened, $i.e.,\ I_{Q_{2}}$ will be clockwise as seen by $E$

Explanation

Reviewed by Dr. Abubacker

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