(d) From, Faraday’s second law,$e = - \frac{d\phi}{db}$ = $- \lbrack 12t - 5\rbrack$ = $- \left\lbrack 12 \times (0.25) - 5 \right\rbrack = + 2$ Now, $\ i = \frac{e}{R} = \frac{2}{20} = 0.1\ A$
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Ph.D. in Physics with 19+ years of teaching experience.