Q. In a transformer, number of turns in the primary are 140 and that in the secondary are 280. If current in primary is $4A$, then that in the secondary is
A) $4\ A$
B) $2\ A$
C) $6\ A$
D) $10\ A$
Explanation
(b) $\frac{V_{p}}{V_{s}} = \frac{i_{s}}{i_{p}} \Rightarrow i_{s} = 4 \times \frac{140}{280} = 2A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.