Q. $5\ cm$ long solenoid having $10\ ohm$ resistance and $5\ mH$ inductance is joined to a $10\ volt$ battery. At steady state the current through the solenoid in $ampere$ will be
A) 5
B) 1
C) 2
D) Zero
Explanation
(b) In steady state current passing through solenoid
$i = \frac{E}{R} = \frac{10}{10} = 1\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.