Q. The number of turns in primary and secondary coils of a transformer is 50 and 200 respectively. If the current in the secondary coil is 4A, then the current in the secondary coil is
A) 1A
B) 2 A
C) 4 A
D) 5 A
Explanation
(a) In a transformer
$\therefore\ \ \ \ \ \ \ \ \ \ \frac{N_{P}}{N_{S}} = \frac{I_{S}}{I_{P}}$
$\ \ \ \ \ \ \ \ \ \ \frac{50}{200} = \frac{I_{S}}{4}$
$\Rightarrow \ \ \ \ \ \ \ \ I_{s} = 1A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.