Q. 2m long wire is moved with a velocity 1${ms}^{- 1}$ in a magnetic field of intensity 0.5 $Wbm^{- 2}$ in direction perpendicular to the field. The emf induced in it will be

A) 2 V
B) 1 V
C) 0.1V
D) 0.5 V
Explanation

(b) The emf induced will be
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ e = vBl = 1 \times 0.5 \times 2 = 1\ V$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.