Q. An aircraft with a wing-span of $40\ m$ files with a speed of $1080\ km\ h^{- 1}$ in the eastward direction at the constant altitude in the northern hemisphere, where the vertical component of earth’s magnetic field is $1.75 \times 10^{- 5}T$. Then the emf that develops between the tips of the wings is

A) $0.5\ V$
B) $0.35\ V$
C) $0.21\ V$
D) $2.1\ V$
Explanation

(c) $L = 40\ m,\ v = 1080km\ h^{- 1} = 300m\ s{ec}^{- 1}$ and $B = 1.75 \times 10^{- 5}T \Rightarrow e = Blv = 1.75 \times 10^{- 5} \times 40 \times 300 = 0.21\ V$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.