Q. A circular coil has 500 turns of wire and its radius is 5 cm. The self inductance of the coil is
A) $25 \times 10^{- 3}mH$
B) $25\ mH$
C) $50 \times 10^{- 3}H$
D) $50 \times 10^{- 3}mH$
Explanation
(b) Self inductance of coil is
$L = \frac{\mu_{0}n^{2}\pi r}{2}$
$\ \ \ = \ \frac{4\pi \times 10^{- 7}}{2} \times (500)^{2} \times \pi \times (5 \times 10^{- 2})\ $
$\ \ \ = 25 \times 10^{- 3}H = 25\ mH$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.