Q. If in a coil rate of change of area is $\frac{5\ metre^{2}}{milli\ second}$, current becomes $1\ amp$ form $2\ amp$ in $2 \times 10^{- 3}\sec$ magnetic field is $1\ tesla$, then self inductance of the coil is
A) $2H$
B) $5\ H$
C) $20\ H$
D) $10\ H$
Explanation
(d) $e = B.\frac{dA}{dt} = L\frac{di}{dt} \Rightarrow 1 \times \frac{5}{10^{- 3}} = L \times \frac{(2 - 1)}{2 \times 10^{- 3}} \Rightarrow L = 10H$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.