Q. An ideal transformer has 100 turns in the primary and 250 turns in the secondary. The peak value of the ac is $28\ V$. The $r.m.s.$ secondary voltage is nearest to
A) $50\ V$
B) $70\ V$
C) $100\ V$
D) $40\ V$
Explanation
(a) $\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{p}} \Rightarrow \frac{250}{100} = \frac{V_{s}}{28/\sqrt{2}} \Rightarrow V_{s} = 50\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.