The magnetic flux across a loop of resistance $10\Omega$ is given by $\phi = 5t^{2} - 4t + 1\ weber$. How much current is induced in the loop after 0.2 sec

Question

Dr. Abubacker · Accepted Answer

(b) Magnetic flux, $\phi = 5t^{2} - 4t + 1\ Wb$
$	herefore\frac{d\phi}{dt} = 10t - 4\ Wb\ s^{- 1}$
The induced $e$mf is $\varepsilon = \frac{- d\phi}{dt} = - (10t - 4)$
At, $t = 0.2\ S,\ \varepsilon = - (10 	imes 0.2 - 4) = 2V$
The induced current is $I = \frac{\varepsilon}{R} = \frac{2V}{10\Omega} = 0.2\ A$

Q. The magnetic flux across a loop of resistance $10\Omega$ is given by $\phi = 5t^{2} - 4t + 1\ weber$. How much current is induced in the loop after 0.2 sec

Explanation

Reviewed by Dr. Abubacker

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