(c) $\eta = \frac{e}{E} \times 100 \Rightarrow e = 0.3\ E$ Now, $i = \frac{E - e}{R} \Rightarrow 12 = \frac{50 - (0.3 \times 50)}{R} \Rightarrow R = 2.9\Omega$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.