Q. A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 rad/s. If the horizontal component of earth’s magnetic field is $0.2 \times 10^{- 4}$T, then the emf developed between the ends of the conductor is
A) 5 $\mu V$
B) 5 mV
C) 50 $\mu V$
D) 50 mV
Explanation
(c) The emf developed between the ends of the conductor
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ e = \frac{1}{2}B\lambda^{2}\omega$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{1}{2} \times 0.2 \times 10^{- 4} \times (1)^{2} \times 5 = 50\mu V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.