Q. The flux associated with coil changes from 1.35 Wb to 0.79 Wb within$\frac{1}{10}$ s. Then the charge produced by the earth coil, if resistance of coil is 7$\ \Omega$ is

A) 0.08 C
B) 0.8 C
C) 0.008 C
D) 8 C
Explanation

(a) As, $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ I = \frac{E}{R} = \frac{d\phi}{Rdt}$
or $Idt = \frac{d\phi}{R}$
Integrating
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \int_{}^{}{Idt = \int_{}^{}\frac{d\phi}{R}}$
or $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ q = \frac{\phi}{R}$
If coil contains N turns, then q $= \frac{N\phi}{R}$
If there is flux change $\Delta\phi$, then
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ q = \frac{N\Delta\phi}{R}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{1}{7} \times (1.35 - 0.79) = 0.08\ C$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.