(d) $\phi = t^{2} + 3t - 7$ $\therefore$ Induced emf $e = - \frac{d\phi}{dt} = - \left( 3t^{2} + 3 \right) = - 3t^{2} - 3$ At $\ \ \ \ \ \ \ \ \ t = 0;\ \ \ \ \ e = - 3\ V$ Therefore, shape of graph will be a parabola not through origin.
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.