(b) $\phi = li$ $\ \ \ \ \ \ \ \ \ \ \ \ l\ = \frac{\phi}{i} = \frac{10 \times 10^{- 6}}{2 \times 10^{- 3}} = 5 \times 10^{- 3} = 5mH$
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Ph.D. in Physics with 19+ years of teaching experience.