(a) $L_{S} = L_{1} + L_{2} = 10H$ …(i)
$L_{P} = \frac{L_{1}L_{2}}{L_{1} + L_{2}} = 2.4H$ …(ii)
On solving (i) and (ii) $L_{1}L_{2} = 24$ …(iii)
Also $\left( L_{1} - L_{2} \right)^{2} = \left( L_{1} + L_{2} \right)^{2} - 4L_{2}L_{2}$
$\Rightarrow \left( L_{1} - L_{2} \right)^{2} = (10)^{2} - 4 \times 24 = 4 \Rightarrow L_{1} - L_{2} = 2H$