Q. The wing span of an aeroplane is 36 m. If the plane is flaying at 400 km$h^{- 1}$, the emf induced between the wings tips is (assume $V = 4 \times 10^{- 5}\ T)$
A) 16 V
B) 1.6 V
C) 0.16 V
D) 0.016 V
Explanation
(c) $l = 36m,\ v = 400\ kmh^{- 1}$
= $\frac{400 \times 1000}{60 \times 60} = \frac{100}{9}\ ms^{- 1}$
= V= 4 $\times 10^{- 5}T\ \ \ \ $
$e = Blv = 4 \times 10^{- 5} \times 36 \times \frac{1000}{9} = 0.16$V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.