Q. A coil of resistance $10\ \Omega$ and an inductance $5H$ is connected to a $100\ volt$ battery. Then energy stored in the coil is
A) $125\ erg$
B) $125\ J$
C) $250\ erg$
D) $250\ J$
Explanation
(d) $U = \frac{1}{2}Li^{2} \Rightarrow U = \frac{1}{2} \times 5 \times \left( \frac{100}{10} \right)^{2} = 250\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.