Q. The self induced emf in a coils of 0.4 henry self inductance when current in it is changing at the rate of 50As$^{-1}$, is
A) $8 \times 10^{- 4}$V
B) $8 \times 10^{- 3}V$
C) 200 V
D) 500 V
Explanation
(c) The induced emf is given by
$\ \ \ \ \ \ \ \ \ \ \ \ |e| = \left( L\frac{di}{dt} \right)$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 0.4 \times 500 = 200\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.