Two coils have a mutual inductance $0.005\ H$. The current changes in the first coil according to equation $I = I_{0}\sin{\omega t}$, where $I_{0} = 10A$ and $\omega = 100\pi\ radian/sec$. The maximum value of e.m.f. in the second coil is

Question

Dr. Abubacker · Accepted Answer

(b) $e = M\frac{di}{dt} = 0.005 	imes \frac{d}{dt}\left( i_{0}\sin{\omega t} ight) = 0.005 	imes i_{0}\omega\cos{\omega t}$
$	herefore e_{\max} = 0.005 	imes 10 	imes 100\pi = 5\pi$

Q. Two coils have a mutual inductance $0.005\ H$. The current changes in the first coil according to equation $I = I_{0}\sin{\omega t}$, where $I_{0} = 10A$ and $\omega = 100\pi\ radian/sec$. The maximum value of e.m.f. in the second coil is

Explanation

Reviewed by Dr. Abubacker

Want more practice?