(b) Induced emf $e = A\frac{dB}{dt}$
$i.e.,e \propto \frac{dB}{dt}$ (= slope of $B - t$ graph)
In the given graph slope of $AB >$ slope of $CD,$ slope in the $'a'$ region $=$ slope in the $'c'$ region = 0, slope in the $'d'$ region = slope in the $'e'$ region $\neq 0$. That’s why $b > (d = e) > (a = c)$