Q. A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4 \times 10^{- 3}Wb$. The self-inductance of the solenoid is
A) 1.0 henry
B) 4.0 henry
C) 2.5 henry
D) 2.0 henry
Explanation
(a) $N\phi = Li \Rightarrow L = \frac{N\phi}{i} = \frac{500 \times 4 \Rightarrow 10^{- 3}}{2} = 1\ henry$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.