Q. A coil of $100\ turns$ and area $5\ square\ centimeter$ is placed in a magnetic field $B\ = \ 0.2\ T$. The normal to the plane of the coil makes an angle of $60{^\circ}$ with the direction of the magnetic field. The magnetic flux linked with the coil is
A) $5 \times 10^{3}\ Wb$
B) $5 \times 10^{- 5}Wb$
C) $10^{- 2}Wb$
D) $10^{- 4}Wb$
Explanation
(a) $\phi = NBA\cos\theta = 100 \times 0.2 \times 5 \times 10^{- 4}\cos{60{^\circ}}$
$= 5 \times 10^{- 3}Wb$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.