A current $I = 10\sin{(100\ \pi t)}A$ is passed in first coil, which induces a maximum emf of $5\ \pi V$ in second coil. The mutual inductance between the coils is

Question

Dr. Abubacker · Accepted Answer

(a) $e = - L\frac{di}{dt};$
$\frac{di}{dt} = 10 	imes 100\pi\cos(100\pi t)$
$L = \frac{e}{\frac{di}{dt}} = \frac{5\pi}{10 	imes 100\pi} = 5 	imes 10^{- 3}H = 5\ mH$

Q. A current $I = 10\sin{(100\ \pi t)}A$ is passed in first coil, which induces a maximum emf of $5\ \pi V$ in second coil. The mutual inductance between the coils is

Explanation

Reviewed by Dr. Abubacker

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