Q. An aeroplane in which the distance between the tips of the wings in 50 m is flying horizontally with a speed of 360 $kmh^{- 1}$ over a place where the vertical component of earth’s magnetic field is $2 \times 10^{- 4}$ $Wbm^{- 2}$. The potential difference between the tips of the wings would be
A) 0.1 V
B) 1.0 V
C) 0.2 V
D) 0.01 V
Explanation
(b) Here, $l = 50\ m,\ v = 360\ kmh^{- 1} = 100\ ms^{- 1}$
$B = 2 \times 10^{- 4}\ Wbm^{- 2}$
Potential difference $e = Blv = 2 \times 10^{- 4} \times 50 \times 100 = 1$V.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.