Q. A power transformer is used to step up an alternating $e$.m.f. of $220\ V$ to $11\ kV$ to transmit $4.4\ kW\ $of power. If the primary coil has 1000 turns, what is the current rating of the secondary? Assume 100% efficiency for the transformer
A) $4\ A$
B) $0.4\ A$
C) $0.04\ A$
D) $0.2\ A$
Explanation
(b) $i_{s} = \frac{P_{s}}{V_{s}} = \frac{4.4 \times 10^{3}}{11 \times 10^{3}} = 0.4\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.