Q.
A straight wire of length $L$ is bent into a semicircle. It is moved in a uniform magnetic field with speed $v$ with diameter perpendicular to the field. The induced emf between the ends of the wire is
A) $BLv$
B) $2BLv$
C) $2\pi BLv$
D) $\frac{2BvL}{\pi}$
Explanation
(d) Induced emf $e = Bvl \Rightarrow e = Bv(2R) = \frac{2BvL}{\pi}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.