Q. The impedance of a R-C circuit is $Z_{1}$ for frequency f and $Z_{2}$ for frequency 2f. Then, $\frac{Z_{1}}{Z_{2}}$ is

A) Between 1 and 2
B) 2
C) Between $\frac{1}{2}$ and 1
D) $\frac{1}{2}$
Explanation

(b) The impedance of R – C circuit for frequency $f_{1}$ is
$Z_{1} = \sqrt{R^{2} + \frac{1}{4\pi^{2}f^{2}C^{2}}}$
The impedance of R – C circuit for frequency 2$f$ is
$\ Z_{2} = \sqrt{R^{2} + \frac{1}{4\pi^{2}{(2f}^{2})C^{2}}}$
or $Z_{2} = \sqrt{R^{2} + \frac{1}{16\pi^{2}f^{2}C^{2}}}$
$\ $Then,$\ \ \ \ \ \ \ \ \ \frac{Z_{1}^{2}}{Z_{2}^{2}} = \frac{R^{2} + \frac{1}{4\pi^{2}f^{2}C^{2}}}{R^{2} + \frac{1}{16\pi^{2}f^{2}C^{2}}}$
Or $\frac{Z_{1}^{2}}{Z_{2}^{2}} = \frac{1 + \frac{1}{4\pi^{2}f^{2}C^{2}R^{2}}}{1 + \frac{1}{16\pi^{2}f^{2}R^{2}C^{2}}}$
Values are greater than 1 then $\frac{Z_{1}}{Z_{2}} =$ lies between 1 and 2.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.