Q. If a current $I$ given by $I_{0}\sin\left( \omega t - \frac{\pi}{2} \right)$ flows in an ac circuit across, which an ac potential of $E = E_{0}\sin{\omega t}$ has been applied, then the power consumption $P$ in the circuit will be
A) $P = \frac{E_{0}I_{0}}{\sqrt{2}}$
B) $P = \sqrt{2}E_{0}I_{0}$
C) $P = \frac{E_{0}I_{0}}{2}$
D) $P = 0$
Explanation
(d) Phase angle $\phi = 90{^\circ},$ so power $P = Vi\cos\phi = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.