Q. If the total charge stored in the $LC$ circuit is $Q_{0},$ then for $t \geq 0$
A) The charge on the capacitor is $Q = Q_{0}\cos\left( \frac{\pi}{2} + \frac{t}{\sqrt{LC}} \right)$
B) The charge on the capacitor is $Q = Q_{0}\cos\left( \frac{\pi}{2} - \frac{t}{\sqrt{LC}} \right)$
C) The charge on the capacitor is $Q = - LC\frac{d^{2}Q}{dt^{2}}$
D) The charge on the capacitor is $Q = \frac{1}{\sqrt{LC}}\frac{d^{2}Q}{dt^{2}}$
Explanation
The correct answer is Option C: The charge on the capacitor is $Q = - LC\frac{d^{2}Q}{dt^{2}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.