Q. A resistor of $R = 6\Omega$, an inductor of L = 1 H and a capacitor of $C = 17.36\ \mu F$ are connected in series with an AC source. Find the Q - factor.
A) 3.72
B) 40
C) 2.37
D) 80
Explanation
(b) Q – factor $= \frac{1}{R}\sqrt{\frac{L}{C}} = \frac{1}{6}\sqrt{\frac{1}{17.36 \times 10^{- 6}}} = 40$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.